MATH SOLVE

4 months ago

Q:
# Write z=-6+6i in polar form

Accepted Solution

A:

z=r(cosα +i*sinα)

r=√(6²+6²)=√(36+36)=√(2*36)=6√2

tanα=6/-6=-1, α=135⁰, or α=3π/4 (if you need in π)

z=6√2(cos 135+i*sin 135)

or

z=6√2(cos 3π/4+i*sin 3π/4)

r=√(6²+6²)=√(36+36)=√(2*36)=6√2

tanα=6/-6=-1, α=135⁰, or α=3π/4 (if you need in π)

z=6√2(cos 135+i*sin 135)

or

z=6√2(cos 3π/4+i*sin 3π/4)