Pre Algebra The booster club sets up a hot dog stand for fundraising at a middle school. The club receives $12 in donations while members set up the stand. The club sells hot dogs for $1.75. Each hot dog costs the club $0.50 and other supplies cost $57. The club wants to know how many dogs they must sell to break even. If the booster club wants to break even by only selling half the number of hot dogs from part b, how much should it charge for each hot dog? Use p to represent the new price for each hot dog.

Answer:A. 36B. 3.5Step-by-step explanation:To solve for the first equation, we could represent the hot dogs as h(1.75-.50), since they are losing .50 cents for each hot dog, h, they make. Since they want to know how many hot dogs they have to sell to equal the amount of money they spent, we can represent it as an equal sign.Now all we have to do is add the constants. Add 12 to our overall equation and subtract 57, since the received $12 in donations and lost $57.Our equation is 12+h1.75=57+.5h We can just put all of the negative numbers on one side and the positive numbers on the other to find out when they will be equal.First, subtract 12 from 57.h1.75=45+.5hNow subtract .5h from both sides.h1.25=45Finally, divide both sides by 1.25.h=36.They will have to sell 36 hot dogs.If they want to sell halve the hotdogs for the same price, simply multiply the current price by 2.The hotdogs will have to cost $3.5.Hope this helps!